6(2x^2-4)=5(x^2-8)

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Solution for 6(2x^2-4)=5(x^2-8) equation: 



6(2x^2-4)=5(x^2-8)

We move all terms to the left:

6(2x^2-4)-(5(x^2-8))=0

We multiply parentheses

12x^2-(5(x^2-8))-24=0



We calculate terms in parentheses: -(5(x^2-8)), so:

5(x^2-8)

We multiply parentheses

5x^2-40

Back to the equation:

-(5x^2-40)



We get rid of parentheses

12x^2-5x^2+40-24=0

We add all the numbers together, and all the variables

7x^2+16=0

a = 7; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·7·16
Δ = -448
Delta is less than zero, so there is no solution for the equation

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